74 lines
2.7 KiB
Python
74 lines
2.7 KiB
Python
from openpyxl import load_workbook
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from PIL import ImageFont
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def get_font_width_ratio(font_path, point_size, char="0"):
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"""
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测量给定字体下指定字符的宽度比例（宽度 / 字体大小）
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通过放大到 200pt 测量消除取整误差。
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"""
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measure_pt = 200 # 足够大，减少 hinting 影响
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# Pillow 的 size 参数需要像素值，我们任选一个 DPI 但最终取比例，所以 DPI 可任意
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dpi = 96
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measure_px = int(measure_pt * dpi / 72)
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font = ImageFont.truetype(font_path, measure_px)
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bbox = font.getbbox(char)
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width_px = bbox[2] - bbox[0]
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ratio = width_px / measure_px # 无量纲比例
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return ratio
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def calc_chars_per_column(workbook_path, sheet_name, column_letter, target_char="中"):
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"""
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计算指定列能容纳多少个 target_char（默认汉字）
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"""
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wb = load_workbook(workbook_path)
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ws = wb[sheet_name]
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# 1. 获取默认字体（Normal 样式）
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# default_font = wb._named_styles["Normal"].font
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# default_font_name = default_font.name or "Calibri"
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# default_font_size = default_font.size or 11 # 磅值
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# 2. 获取默认字体下数字 '0' 的宽度比例
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# 需要找到默认字体文件路径（简单方案：使用系统字体名，PIL 能自动查找）
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zero_ratio = get_font_width_ratio(
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"Calibri.ttf", 11, "0"
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)
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standard_char_width_pt = 11 * zero_ratio # 标准字符宽度（点）
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# 3. 获取目标字体（宋体 8 号 = 5pt）下汉字的宽度比例
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target_font_name = "simsun.ttc" # 宋体
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target_font_size_pt = 8
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han_ratio = get_font_width_ratio(target_font_name, target_font_size_pt, target_char)
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han_width_pt = target_font_size_pt * han_ratio
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# 4. 列宽（字符数）
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col_width_chars = ws.column_dimensions[column_letter].width
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print("列宽：", col_width_chars, "字符")
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# 5. 左右内边距 + 右边框线的经验值（点）
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# 根据实测，对于小列宽，固定边距约为 3pt（相当于 4~5 像素在 96DPI 下）
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padding_pt = 0
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total_width_pt = (
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col_width_chars * standard_char_width_pt + padding_pt * 2 + 0.5
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) # 右边框约 0.5pt
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# 6. 计算可容纳汉字数
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max_count = int(total_width_pt // han_width_pt)
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# print(f"默认字体: {default_font_name} {default_font_size}pt")
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print(f"标准字符宽度: {standard_char_width_pt:.3f} pt")
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print(f"目标汉字宽度: {han_width_pt:.3f} pt")
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print(f"列总宽度: {total_width_pt:.3f} pt")
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print(f"可容纳汉字数: {max_count}")
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return max_count
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# 使用示例
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if __name__ == "__main__":
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# 替换为你的文件路径和工作表名
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count = calc_chars_per_column("测试.xlsx", "Sheet1", "AA")
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